Please help ??

Dear student,

If the number 4n,  for any n, were to end with the digit zero, then it should be divisible by 5. That is, prime factorisation of 4n would contain the prime factor 5. This is not possible because 4n=(22)n=22n.   So, the only prime in the factorisation of 4n is 2.


So, by uniqueness of the fundamental theorem of Arithmetic, there are no other primes in the factorisation of 4n

Hence, there is no natural number 'n' for which 4n  ends with the digit zero. 

Regards

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