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Dear Student,Given,R=10Ω,r=0.01cm=0.01×10-2=10-4m,ρ=50×10-8ΩmArea of cross section of the wire is,A=πr2=3.14×10-42=3.14×10-8m2We know,R=ρlALength of the wire is,l=RAρ=10×3.14×10-850×10-8=3.14×10-750×10-8=0.0628×10=0.628mRegards

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