Please solve Q. Evaluate : ∫ x 2 - 1 x x 4 + 3 x 2 + 1 d x Share with your friends Share 1 Aarushi Mishra answered this ∫x2-1xx4+3x2+1dx=∫x2-1xx2x2+3+1x2dx=∫x2-1x2x2+3+1x2dx=∫x2-1x2x2+2+1x2+1dx=∫x2-1x2x2+2×x×1x+1x2+1dx=∫1-1x2x+1x2+1dxLet u=x+1xdy=1-1x2I=∫1t2+1dtUse ∫1x2+a2dx=ln x+x2+a2+cI=ln t+t2+1+c=ln x+1x+x+1x2+1+c 0 View Full Answer