Please solve
Q. Evaluate :
x 2 - 1 x x 4 + 3 x 2 + 1 d x

x2-1xx4+3x2+1dx=x2-1xx2x2+3+1x2dx=x2-1x2x2+3+1x2dx=x2-1x2x2+2+1x2+1dx=x2-1x2x2+2×x×1x+1x2+1dx=1-1x2x+1x2+1dxLet u=x+1xdy=1-1x2I=1t2+1dtUse 1x2+a2dx=ln  x+x2+a2+cI=ln  t+t2+1+c=ln  x+1x+x+1x2+1+c

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