Please solve question 3

3 .         D r a w   A B C   w h o s e   l e n g t h   o f   a l l   3   m e d i a n s   6   c m ,   7 . 2   c m .   6 . 6   c m   .


 

Dear Student,

Please find below the solution to the asked query:

We follow these steps:

We know all three medians intersect at a single point and Medians cuts each other at a ratio of 2 : 1 .

Step 1 : We Draw a line ED as 13 of side of 6 cm  , So we get ED  = 2 cm

Step 2 : Now take Radius of 13 of side of 6.6 cm ( 2.2 cm ) and center " E "  draw an arc and Radius of 13 of side of 7.2 cm ( 2.4) and center " D "  draw an arc that intersect previous arc at " G " .

Step 3 : We extend line GE to X and get line " GX "  and extend line DG to Y and get line " DY "

Step 4 : With radius of GE and center " E "  we draw an arc that intersect our line GX at " A " .

Step 5 : Join AD and and extend it to point B as AD  =  BD .

Step 6 : Now we take radius double the DG or 23 of side of 7.2 cm  ( 4.8 cm ) and draw an arc by taking center " G "  that arc intersect our line DY at " C " .

Step 7 : Join AC and BC . We get our required triangle .



Hope this information will clear your doubts about Constructions.

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards 

  • 0
What are you looking for?