Please solve question no.6.

Dear Student
Effort arm = 2 cm
Load arm = 8.0 cm
Given effort =10kgf
(i) Mechanical advantage M.A = Effort arm/Load arm = 2/8 = 0.25
(ii) load = M.A × effort = 0.25 × 10 = 2.5 kgf
The pair of scissors acts as a speed multiplier because MA < 1.

Regards

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