Please solve the 22 number.
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Q.22. Two resistors of resistance 4 Ω and 6 Ω are connected in parallel to a cell to draw current 0.5 A from the cell.
(a) Draw a labelled diagram of the arrangement.
(b) Calculate the current in each resistor.
Ans. 0.3 A in 4 Ω and 0.2 A in 6 Ω

Dear student,

a)

b) Effective Resistence in  combination is given by1R=1R1+1R21R=14+161R=3+2121R=512R=125ΩBy ohm's lawV=IRV=0.5×125V=1.2 voltsince the voltage remain same in parallel combinationNow, current through resistence 4Ω, I1=VR1I1=1.24I1=0.3 Aand current through resistence 6Ω, I2=VR2I2=1.26I2=0.2A
Regards

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