# Please tell the answe of Q.9 ,Q.10 , Q.11 and Q.12 Q9. 86 – [ 15x – 7 (6x – 9) – 2{10x – 5(2 –3x )}] Q10. 12x – [3x3 + 5x2 – { 7x2 – (4 – 3x – x3) + 6x3} – 3x] Q11. 5a – [a2 – {2a (1 – a + 4a2)– 3a (a2 – 5a – 3)}] –8 a Q12. 3 – [x – {2y –(5x + y – 3) + 2x2} – ( x2 – 3y ) ]Please tell the answe of Q.9 ,Q.10 , Q.11 and Q.12

Dear Student,

$9\right)\phantom{\rule{0ex}{0ex}}86-\left[15x-7\left(6x-9\right)-2\left\{10x-5\left(2-3x\right)\right\}\right]\phantom{\rule{0ex}{0ex}}⇒86-\left[15x-42x+63-2\left\{10x-10+15x\right\}\right]\phantom{\rule{0ex}{0ex}}⇒86-\left[63-27x-2\left\{25x-10\right\}\right]\phantom{\rule{0ex}{0ex}}⇒86-\left[63-27x-50x+20\right]\phantom{\rule{0ex}{0ex}}⇒86-\left[83-77x\right]\phantom{\rule{0ex}{0ex}}⇒86-83+77x\phantom{\rule{0ex}{0ex}}\overline{)⇒77x+3}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}10\right)\phantom{\rule{0ex}{0ex}}12x-\left[3{x}^{3}+5{x}^{2}-\left\{7{x}^{2}-\left(4-3x-{x}^{3}\right)+6{x}^{3}\right\}-3x\right]\phantom{\rule{0ex}{0ex}}⇒12x-\left[3{x}^{3}+5{x}^{2}-\left\{7{x}^{2}-4+3x+{x}^{3}+6{x}^{3}\right\}-3x\right]\phantom{\rule{0ex}{0ex}}⇒12x-\left[3{x}^{3}+5{x}^{2}-\left\{7{x}^{2}-4+3x+7{x}^{3}\right\}-3x\right]\phantom{\rule{0ex}{0ex}}⇒12x-\left[3{x}^{3}+5{x}^{2}-7{x}^{2}+4-3x-7{x}^{3}-3x\right]\phantom{\rule{0ex}{0ex}}⇒12x-\left[-10{x}^{3}-2{x}^{2}+4-6x\right]\phantom{\rule{0ex}{0ex}}⇒12x+10{x}^{3}+2{x}^{2}-4+6x\phantom{\rule{0ex}{0ex}}\overline{)⇒10{x}^{3}+2{x}^{2}+18x-4}\phantom{\rule{0ex}{0ex}}$
for solution to rest of the sub parts , kindly post the remaining questions in a separate thread.

Regards,

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