# Please tell this also.

Dear Student,

Solution)

P(x) = x^{2} - 5x + 4

P(3) = 3^{2} - 5 × 3 + 4

P(3) = 9 - 15 + 4

P(3) = -2

Since, -2 is the remainder.

Therefore, 2 must be added to P(x) So that 3 will be a zero of the polynomial.

Verification:

P(x) = x^{2} - 5x + 4

Adding 2,

P(x) = x^{2}- 5x + 6

P(3) = 3^{2} - 5 × 3 + 6

P(3) = 9 - 15 + 6

P(3) = 15 - 15

P(3) = 0

Hence, 2 is supposed to be added to the polynomial, for 3 to become a zero of the polynomial.

Regards!

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