Please tell this also.
Dear Student,
Solution)
P(x) = x2 - 5x + 4
P(3) = 32 - 5 × 3 + 4
P(3) = 9 - 15 + 4
P(3) = -2
Since, -2 is the remainder.
Therefore, 2 must be added to P(x) So that 3 will be a zero of the polynomial.
Verification:
P(x) = x2 - 5x + 4
Adding 2,
P(x) = x2- 5x + 6
P(3) = 32 - 5 × 3 + 6
P(3) = 9 - 15 + 6
P(3) = 15 - 15
P(3) = 0
Hence, 2 is supposed to be added to the polynomial, for 3 to become a zero of the polynomial.
Regards!