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plllzz ans.6th no link pllzz If all volumes are measured at the Fame temperature and pressure, calculate the volume of N20 required to give 150 crn3 of steam. 1300 5. Calculate the volume Of HCI gas formed and chlorine gas required when 20 mL Of methane reacts completely with [Ans•. HO go mL; 80 mLl chlorine at STP. 6. What volume of air (containing 20% 02 by volume) will be required to burn completely 10 cm3 each of methane and acetylene? Ammonia may be oxidised to nitrogen monoxide (or nitric oxide) in the presence of a catalyst according to the following 7. equation : 4NH3 + 502 4NO+ 61-120 [f 27 litres of reactants are consumed, what volume of nitrogen monoxide is produced at the same temperature and 12 8. 112 cm3 of H2S@) is mixed with 120 cm3 of C12(g) at STP to produce HCl(g) and sulphur(s). Write a balanced e for this reaction and calculate the (i) volume of gaseous product formed, and (ii) composition Of the resulting mixture. IAns: * 2HCl S; (i) 224 9. Given that: 202 Calculate the volume of oxygen required when a mixture of 22.4 drn3 of methane and 11.2 dm3 of (AfS.•-soa dn completely as shown by the chemical equations above.

Dear Student,

Burning of methane:
CH₄ + 2O₂ → CO₂ + 2H₂O

According to the reaction,
For complete burning 1 volume of methane, 2 volumes of Oxygen is required.
Hence, for burning 10 cm³ of methane, 20 cm³ of oxygen is required.
Since, air contains 20% of oxygen. So 100 cm³ of air will be required containing 20 cm³ of oxygen.

Burning of acetylene:
C₂H₂ + 52O₂ → 2CO₂ + H₂O

According to the reaction,
For complete burning 1 volume of acetylene, 5/2 volumes of Oxygen is required.
Hence, for burning 10 cm³ of acetylene, 52×10 = 25 cm³ of oxygen is required.
Since, air contains 20% of oxygen.
So, 20 cm³ oxygen is present in 100 cm³
Therefore, 25 cm³ oxygen will be present in 10020×25 = 125 cm3
Hence, 125 cm³ of air will be required containing 25 cm³ of oxygen

Therefore, total amount of air = 100+125=225 cm³

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