Pls answer this Given n resistors each of resistance 'R'. How will you combine them to get the (i) maximum (ii) minimum effective resistance? What is the ratio of the maximum to minimum resistance? Share with your friends Share 0 Sagar Kumar answered this Dear Student,We know that, For maximum effective resistance, the resistors must be connected in series combination.So, Reff=R+R+R+..........n timesTherefore, Reff=nR =Rmax .................(1)Now, For minimum effective resistance, the resistors must be connected in parallel combination.So, 1Reff=1R+1R+1R ........................n times⇒1Reff=nRTherefore, Reff=Rn=Rmin ........................(2)Ratio of the maximum to minimum resistance RmaxRmin=nRRn=n21Therefore, Rmax:Rmin=n2:1Regards 0 View Full Answer Neha Thomas answered this For maximum effective resistance, the resistors must be connected in series combination. If then are n resistors each of resistance R, then the maximum effective resistance =nR For minimum effective resistance, the resistors must be connected in parallel combination. So, the minimum effective resistance =nR Ratio of the maximum to minimum resistance is (R/n)nR=n2:1. 3 Liyana answered this Thank you! 0 Ayush Pandey answered this How are you may God bless you 1 Neha Thomas answered this Your welcome . 1 Swarnim Verma answered this We would combine i) the resistors in series (end to end) combination to get the maximum effective resistance. i)the resistors in parallel combination to get the minimum effevtive resistance. 0
