Dear Student, Look that the electric field due to each plate is E=σ2ε0So for two plates the net electric field will be ,,Enet=2E=2×σ2ε0=σε0 Regards

Pls answer this Q.

Pls answer this Q. Two rectangular tnfinite charged surface chsrqe tonsity are placed AS sliown in figure, then magnitude of field pont (O. O, d) d is small. bo (O) none of those

Dear Student,

​ L o o k t h a t t h e e l e c t r i c f i e l d d u e t o e a c h p l a t e i s E = \frac{σ}{2 ε_{0}} S o f o r t w o p l a t e s t h e n e t e l e c t r i c f i e l d w i l l b e,, E_{n e t} = 2 E = 2 \times \frac{σ}{2 ε_{0}} = \frac{σ}{ε_{0}}

Regards