Pls explain the answers of all the questions Pls answer by this night as i have my exams tomorrow morning by 7 am Topic : Vectors Share with your friends Share 0 Manbar Singh answered this Dear Student, 73. We have,z1 = 4 + 5i ; z2 = -3 +2iNow, z1z2 = 4+5i-3+2i⇒z1z2 = 4+5i-3+2i × -3-2i-3-2i⇒z1z2 = -12-8i-15i+109+4⇒z1z2 = -2-23i13⇒z1z2 = -213 - 23i1375. i13+ i14+ i15 + i16= i26× i + i27 + i27×i + i28= -16× i + -17 + -17×i + -18= i - 1 - i +1= 0conjugate of i13+ i14+ i15 + i16 = 077.Let α = 7i ; β = -7iNow, α + β = 7i - 7i = 0Now, α β = 7i -7i = -7i2 = 7Now, required quadratic equation is , x2 - α + βx + α β = 0⇒x2 -ox + 7 = 0⇒x2 + 7 =0 Kindly ask the remaining queries in different threads. Regards -1 View Full Answer
