Pls solve Q6:

6. x 2   +   1 x 2     3

Dear student,I am assuming to factorise;Q6.x2+1x2-3= (x2+1x2-2)-1[(x-y)2=x2+y2-2xy]= (x-1x)2 -(1)2        [x2-y2=(x+y)(x-y)]= (x-1x+1)(x-1x1)Regards

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