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pls solve this question.... if (1+2i)(2+3i)(3+4i)= x+iy.Show that x^2 +y^2 =1625.

$Given (1 + 2 i) (2 + 3 i) (3 + 4 i) = x + i y \Rightarrow (1 + 2 i) (6 + 8 i + 9 i + 12 i^{2}) = x + i y \Rightarrow (1 + 2 i) (17 i + 6 - 12) = x + i y \Rightarrow (1 + 2 i) (17 i - 6) = x + i y \Rightarrow 17 i - 6 + 34 i^{2} - 12 i = x + i y \Rightarrow 5 i - 40 = x + i y \Rightarrow x = - 40 and y=5 x^{2} + y^{2} = (- 40)^{2} + (5)^{2} = 1600 + 25 = 1625$

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