Pls solve this question..

Dear Student ,

For preimage of 5 we have:f(x)=x2+1=5x2+1=5x2=4x=4x=±2So, x2,2For preimage of5 we have:f(x)=x2+1=5x2=6x2=6 there is no real value of x for which x2=-6Hence,no possible preimage.So,xϕ Therefore option  c -2,2,ϕ is correct.

Regards

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