Dear student ⇒0 07=0 28x⇒x=14Therefore,PNon- defective from T2=0 8×1-x100 93=810×394093100=7893 Regards

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PLS SOVE

Dear student

⇒0.07=0.28x ⇒x= \frac{1}{4} Therefore, P (Non - defective from T_{2}) = \frac{0.8 \times (1 - \frac{x}{10})}{0.93} = \frac{\frac{8}{10} \times \frac{39}{40}}{\frac{93}{100}} = \frac{78}{93}

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