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Solution:
Na (Z=11) has electronic configuration 2,8,1.
It can easily lose 1 electron to acquire stable noble gas configuration, forming Na+ ion.
Number of electrons present in Na+ ion are 11-1 = 10
S (Z=16) has electronic configuration 2,8,6.
It can easily gain 2 electron to acquire stable noble gas configuration, forming S2- ion.
Number of electrons present in S2- ion are 16+2 = 18
Na (Z=11) has electronic configuration 2,8,1.
It can easily lose 1 electron to acquire stable noble gas configuration, forming Na+ ion.
Number of electrons present in Na+ ion are 11-1 = 10
S (Z=16) has electronic configuration 2,8,6.
It can easily gain 2 electron to acquire stable noble gas configuration, forming S2- ion.
Number of electrons present in S2- ion are 16+2 = 18