# plz ans it

5x = 1000
5x = 103
Taking log on both hand side we get
log 5x = log 103

xlog 5 = 3 log 10                               ( As we know log ab = b log a )

x =

0.5y = 1000
${\left(\frac{5}{10}\right)}^{y}$ = 103
Taking log on both hand side we get
log ${\left(\frac{5}{10}\right)}^{y}$ = log 103

y [ log 5 - log 10 ] = 3 log 10                 ( As we know log$\left(\frac{a}{b}\right)$  = log a - log b  )

y =
Now substitute value of x and y in   , we get

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$⇒$                                ( Ans )

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