plz ans this plz ans this log. (i — 2x) 5 $2 — 5. Share with your friends Share 0 Varun Rawat answered this 9log31 - 2x = 5x2- 5⇒ log3 9log31 - 2x = log35x2- 5⇒ log31 - 2x × log39= log35x2- 5⇒ log31 - 2x × log332 = log35x2- 5⇒ 2log31 - 2x = log35x2- 5 as, log332 = 2log33 = 2 × 1 = 2⇒ log31 - 2x2 = log35x2- 5⇒ 1 - 2x2 = 5x2- 5 ⇒1 + 4x2 - 4x = 5x2- 5⇒ x2 + 4x - 6 = 0a = 1 ; b = 4 ; c = -6Now, D = b2 - 4ac= 42 - 4 × 1 × -6= 16 + 24= 40So, x = -4 ± 402 = -4 ± 2102⇒x = -10 + 2 and x = 10 - 2 rejectedAs log31 - 2x = log31 - 210 + 4 = log35-210 = log3a negative quantity = not definedSo, x = -10 + 2 0 View Full Answer Ahmad answered this answer 0