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Dear student,

T h e m i n u t e h a n d m o v e s t h r o u g h 2 π \times \frac{50}{60} = \frac{5 π ​}{3} r a d i a n s . S i n c e t h e l e n g t h o f t h e m i n u t e h a n d i s 2.5 c m, t h e d i s \tan c e m o v e d b y t h e t i p o f t h e h a n d i s g i v e n b y t h e f o r m u l a, l = r θ = \frac{5}{2} \times \frac{5 π ​}{3} = \frac{25 \times 3.14}{6} = 13.08 c m

Regards