Plz expain how to solve dis...

V   n N


1 )   sin ( n x ) < sin x 2 )     sin ( n x ) < n sin x 3 )     sin ( n x ) n sin x 4 )   sin ( n x ) sin n
 

Hi, 
Taking third option, 

For n=0, |sin(n*0)| = 0, n|sin(x)| = 0 is true. 

Suppose that |sin(nx)|  n|sin(x)|.


So it is true 

 

  • 1
What are you looking for?