Plz expain how to solve dis...
Hi,
Taking third option,
For n=0, |sin(n*0)| = 0, n|sin(x)| = 0 is true.
Suppose that |sin(nx)| n|sin(x)|.
So it is true
Taking third option,
For n=0, |sin(n*0)| = 0, n|sin(x)| = 0 is true.
Suppose that |sin(nx)| n|sin(x)|.
So it is true