plz'justify' the answer to me.
ithink it should be like n answer doesnt match.

P(odd/even)... (using conditional probability)
...

Dear Rudram,
number of outcomes when it is an even at one throw and odd at another throw are 3*3 = 9
even numbers are 2,4,6 and odd are 1,3,5
so it is said in the question that even at one throw and odd at another throw
therefore in first throw there are 3 possibilities and similarly in 2nd throw there are 3 possibilities
thus the favourable outcomes = 3*3 = 9
and the required probability
= 9/36
= 1/4

hope this helps you

 

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