Plzz ans fast!!!
Q). In given fig., AB is diameter of circle C D A B and B A D = 60 ° . Find A C D .

Dear Student,

Here is the solution of your asked query:

Since, AB is the diameter of circle so we have;ACB = 90°       {Angles in a semicircle }BAD=60°We know that sum of opposite angles of cyclic quadrilateral is 180°, so we have;BAD+BCD=180°60°+ACB+ACD=180°ACB+ACD=120°                  {since ACB = 90°}90°+ACD=120° ACD=30°                  
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