Plzz fast i have exams 2moro. Dont provide any link plzzzzz
Dear student
Regards
Taking m=p and n=q
Let a and d be the first term and common difference of A.P respectively.
Given, ap = q and aq = p
ap = q
⇒ a + (p –1) d = q ... (1)
aq = p
⇒ a + (q – 1) d = p ... (2)
Solving (1) and (2), we have
When d = –1, we get
a + (p – 1) (–1) = q (Using (1))
⇒ a = q + p – 1 = p + q – 1
ap + q = a + (p – q + 1)d
∴ ap + q = (p + q – 1) + (p – q + 1) (–1) = (p + q – 1) – (p + q – 1) = 0
Regards