Plzz fast i have exams 2moro

Dear Student,

To prove: 1 + 3sinθ - 4sin3θ1 - sinθ = 1 + 2sinθ2Proof: LHS = 1 + 3sinθ - 4sin3θ1 - sinθ= 1 - sinθ + 4sinθ - 4sin3θ1 - sinθ= 1 - sinθ + 4sinθ1 - sin2θ1 - sinθ= 1 - sinθ + 4sinθ1 + sinθ1 - sinθ1 - sinθ= 1 - sinθ1 + 4sinθ1 + sinθ1 - sinθ= 1 + 4sinθ + 4sin2θ= 1 + 22sinθ1 + 2sinθ2= 1 + 2sinθ2= RHSHence, proved

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