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Plzz find it Cknetics — Some lamentals s e a 30 he o c n 8 80*-e_

Dear student,                                                                                                                                                                         
Please find below the solution to the asked query       
          
1. Haemophilia is an X linked recessive disease. Male (father) cannot be carrier. If haemophilic gene is present on X chromosome of male, it is always affected.

Now, if the woman would is a carrier, her genotype would be X^hX. This woman marries a normal man whose genotype would be XY. Lets make a cross:

	Xh	X
X	XhX ​(Carrier)	XX ​(Normal)
Y	XhY ​(Affected)	XY ​(Normal)

From the above cross,  we can infer that 25% of  the children suffer from haemophilia and 75% are unaffected (50% normal and 25% carrier).

2. If a haemophilic woman (X^hX^h) marries a normal man (XY), the cross would be as follows:

	Xh	Xh
X	XhX ​(Carrier)	XhX ​(Carrier)
Y	XhY ​(Affected)	XhY ​(Affected)

From the above cross, we can infer that 50% of  the children suffer from haemophilia and 50% are unaffected (carrier).

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