POQ is a straight line. OT bisects <POR and OS bisects <QOR. Show that <SOT is a right angle. POQ is a straight line. OT bisects <POR and OS bisects <QOR. Show that <SOT is a right angle
Given - <POQ is a straight line , OT bisects <POR , OS bisects <QOR To proof : <SOT is a right angle Proof : POQ is a straight line , & OT bisects <POR , so <POT = <TOR --(1) POQ is a st. line and OS bisects <QOR , SO <ROS = <SOQ --(2) since OR stands on POQ then ,<POR+<ROQ = 180 degree <POT+<TOR+<ROS+<SOQ= 180 degree <TOR+<TOR+<ROS+<ROS=180 degree ----(from 1&2) = 2(<TOR+<ROS) = 180 degree <TOR+<ROS = 180/2 <TOR+,ROS = 90 degree therefore <SOT = 90 degree Hence proved.