pq and rq are chords of a circle equidistant from the centre .prove that the diameter passing through q bisects angle pqr and angle psr pls answer Share with your friends Share 8 Manbar Singh answered this GIVEN :PQ and RQ are the chords of a circle with centre at O, such that chords areequidistant from centre O.TO PROVE :Diameter QS passing through O bisects ∠PQR and ∠PSR.PROOF :We know that chords that equidistant from the centre are equal in length.So, PQ = RQIn ∆PQS and ∆RQS PQ = RQ Proved above∠QPS = ∠QRS Angle in a semi circle is right angle, so ∠QPS = ∠QRS = 90° QS = QS Common∆PQS ≅ ∆RQS SAS⇒∠PQS = ∠RQS CPCTand ∠PSQ = ∠RSQ CPCT⇒QS bisects ∠PQR and ∠PSR. 21 View Full Answer Bhargavi Subash answered this pls answer quickly -6