# PQ * P3= 57Q.P=? Q=?

We have   PQ $×$ P3  = 57Q

We can see that unit digit of our solution is obtain by  Q $×$ 3  = Q , from that we get unit digit same

First we can check for 0  , And get

0  $×$ 3  = 0

Now we check that

20 $×$ 23   = 460
or
30 $×$ 33  = 990

Here we can't get 570 as given in our equation .
So now we check for Q  =  5
So,
$×$ 3  =  15

here we get unit digit of solution is same ( 5 )

So now we get

25 $×$ 23  =  575

So ,

P = 2 And Q  =  5                              ( Ans )

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