PQRS is a parallelogram whose vertices are P(1,4) Q(7,11) R(a,4) S(1,-3) find the value of a Share with your friends Share 1 Abhishek Jha answered this Dear student, Here is the solution of your asked query: The vertices of parallelogram are P1,4; Q7,11; Ra,4 and S1,-3.Since opposite sides of parallelogram are equal, so PQ=RSNow we have;PQ=7-12+11-42 and RS=1-a2+-3-42so; 1-a2+-3-42=7-12+11-42⇒1-a2+49=36+49⇒1-a2=36⇒1-a=±6⇒1-a=6 and 1-a=-6⇒a=-5 and a=7therefore value of a is -5 or 7 Regards 2 View Full Answer Shaurya Singhal answered this Since PQ = RS (in a parallelogram opposite sides are parallel and equal) so apply distance formula in this and find the value of R. 0 Nandini Gupta answered this I need the answer to check my answer thanks for you advise 2
