pqrs is parallelogram where pq is parallel to rs prove that ar of SOR=AR OF PQO

PQRS is a parallelogram. Suppose O is the point of intersection of the diagonals PR and SQ.

ΔPRS and ΔPQS are on the same base PS and between the same parallels PS and RQ.

∴ area (ΔPRS) = area (ΔPQS)

⇒ area (ΔPRS) – area (ΔPOS) = area (ΔPQS) – area (ΔPOS)

⇒ area (ΔSOR) = area (ΔPOQ)

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is o is intersecting point of diameter ?

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 no

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it can be any point inside ||gram

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Plz provide the diagram if possible !! 

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