Login

prove sin(a+b)sin(a-b) =sin^2a-sin^2b

$Given sin(a+b)sin(a-b) = (\sin a \cos b + \cos a \sin b) (\sin a \cos b - \cos a \sin b) = (\sin a \cos {b)}^{2} - (\cos a \sin b)^{2} = \sin^{2} a \cos^{2} b - \cos^{2} a \sin^{2} b = \sin^{2} a (1 - \sin^{2} b) - (1 - \sin^{2} a) \sin^{2} b = \sin^{2} a - \sin^{2} a \sin^{2} b - \sin^{2} b + \sin^{2} a \sin^{2} b = \sin^{2} a - \sin^{2} b$

0

View Full Answer

Copyright © 2024 Aakash EduTech Pvt. Ltd. All rights reserved.

Aakash EduTech Pvt. Ltd.

What are you looking for?