prove tan inverse(3sin2alpha/5+3cos2 alpha)+tan inverse(1/4tan alpha)=alpha Share with your friends Share 3 Rahul Raj answered this LHS = tan-13 sin 2α5 + 3 cos 2α + tan-1tan α4=tan-13 × 2 sin α . cos α5 + 32 cos2α-1 + tan-1tan α4=tan-16 sin α . cos α2 + 6 cos2α+ tan-1tan α4=tan-13 sin α . cos α1 + 3 cos2α+ tan-1tan α4=tan-13 tan αsec2α + 3 + tan-1tan α4=tan-13 tan α4+tan2α + tan-1tan α4=tan-134tan α1 + tan2α4 + tan-1tan α4=tan-1tan α - tan α41 + tan α .tan α4+ tan-1tan α4=tan-1tan α - tan-1tan α4+ tan-1tan α4=tan-1tan α=α=RHS 16 View Full Answer Aashi answered this The answer is given in the image -2
