prove that diagnals of a rectangle are of equal length

ABCD is a rectangle. AC and BD are the diagonals of rectangle.

In ΔABC and ΔBCD, we have

AB = CD (Opposite sides of rectangle are equal)

∠ABC = ∠BCD  ( Each equal to 90°)

BC = BC (Common)

∴ ΔABC  ΔBCD (SAS congruence criterion)

⇒ AC = BD [c.p.c.t]

Hence, the diagonals of a rectangle are equal.

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