Prove that medians of equilateral triangle are equal.

Consider an equilateral ΔABC. Let AD, BE and CF be the medians of BC, AC and AB respectively.

We know that in an equilateral Δ, medians are altitudes as well.

Let AB = BC = AC = *x* [say]

In right ΔABD, by pythagoras theorem,

AB^{2} = AD^{2} + BD^{2}

In right ΔBEC,

BC^{2} = BE^{2} + CE^{2}

Similarly, we can show that CF = $\frac{\sqrt{3}x}{2}$.

Thus, AD = BE = CF.

Hence we are done.

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