prove that sec square (tan inverse 2) +cosec square (cot inverse 3) =15

L.H.S.=sec2tan-12+cosec2cot-13            =1+tan2tan-12+1+cot2cot-13            =1+tantan-122+1+cotcot-132            =1+22+1+32            =1+4+1+9            =15            =R.H.S.Hence Proved.

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 secsquare(taninverse 2)=sec ^2 (sec ^-1 √5  )=(√5)^2=5 ...............1

similarly,

cosecsquare(cotinverse 3)=cosec^2 (cosec^-1√10)=(√10)^2=10.............2

ADD 1 and 2

you get the answer

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