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prove that tan -1(1) + tan-1(2) + tan-1(3) = pie.

=tan-11+(tan-12+tan-13)

=^/4  +(^/2-cot-12 ) + (^/2-cot-13)

=^/4+^ - tan-11/2+tan-11/3

=^/4 - ^ - tan-1{ (1/2+1/3)/(1-1/2*1/3) }

=^+  ^/4 - tan-11

=^

  • -11
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tan-1(1) + tan-1(2) + tan-1(3) 

tan-1(1+2/1-1*2) + tan(3)     (tan(A+B) = tanA + tanB/1-tanAtanB)

tan-1(-3) + tan-1(3)

tan-1(-3+3/1+3*3)

tan-1(0/1+9)

tan-1(0)

pie

hence proved

  • 8

one best way to look is

sides 1 , 2 and 3 resembles a triangle with 0 area.

thus, sum of all the three angles must be 180o.

  • -27

nah my approach to this question as mentioned is wrong... !!

  • -11

srry... i don't listen tribal songs... :P

  • -18
Pink panther
  • -21
its very simple refer pg 166
  • -24
tan-11+tan-12 +tan-13=pi
 we know that tan-1x +tan-1y +tan-1z=pi then  x +y +z =xyz
​so 1+2+3=1*2*3
6=6
hence proved
 
  • -14
All the above anwers are wrong
  • -15
Refer rd pg 4.72..
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Solution :

Tan-11+ Tan-12+ Tan-13=?
Solution:
Tan-11=π/4
Tan-12+ Tan-13= Tan-12+ Tan-13/ 1-Tan-12. Tan-13= Tan-1 -1=nπ-π/4=π-π/4
So,Tan-11+ Tan-12+ Tan-13=π(Answer)
 
  • -15
Tan^-1 (1)+tan^-1 (1/2)+tan^-1 (1/3)
  • -15
by this we can solve it

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tan^-1(2)=π/2-tan^-1(1/2)
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Easily solved I hope it helped to all😊

  • 7
Please find this answer

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Hope it can help you

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Solved by Kumar vidyanand Sagar

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tan 1/2+ tan 1/3= ........
  • -1
Please can anyone answer the 25th question??

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