Prove that the median from the vertex of an isosceles triangle is the bisector of the vertical angle. 

Consider an isosceles triangle ABC having AD as the median and AB = AC.

Given AD is the median.

⇒ BD = DC

In Δ ABD and Δ ADC, we have

AB = AC

BD = DC

and AD = AD

Therefore, Δ ABD  Δ ADC  [SSS property]

⇒ ∠1 = ∠2  [cpct] 

Hence, the median from the vertex of an isosceles triangle is the bisector of the vertical angle.

  • 7

two  sides of iso. tri. are equal,

one con. angle will be equal and

the median(side) will be common.....

hence,by SAS congurence the triangles are congurent,

so,median will bisect the vertical angle (by c.p.c.t)

  • -3

thanx

  • 1
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