Q.13. Find the value of
cos 2 20 °   cos 2 70 ° sin 2 31 °   sin 2 59 ° + sin 2 64 ° + cos 64 ° . sin 26 °

Dear student,


Assuming the question is  cos220+cos270sin231+sin259+sin264+cos64.sin26 and solving furtherWe havecos220+cos270sin231+sin259+sin264+cos64.sin26=cos220+cos290-20sin231+sin290-31+sin264+cos64.sin90-64=cos220+sin220sin231+cos231+sin264+cos64.cos64          --[using sin (90-θ)=cosθ and cos(90-θ )=sinθ ]=11+sin264+cos264                   --[using sin2θ+cos2θ=1]=1+1                                           --[using sin2θ+cos2θ=1]     =2

Regards

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