Q.13. In the given figure, ABC is a triangle in which AB = AC and D is a point on AB. Through D, a line DE is drawn parallel to BC and meeting AC at E. Prove that AD = AE.

Only the thing in question is that we have to prove angleADE=angleAED. Then we know that --angle opposite to equal sides are equal and we also know that angleADE=angleAED. Therefore AD=AE.

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