Q.16. In the figure, AP = 2 cm, BP = 6 cm and CP = 3 cm, find DP


(A) 6 cm
(B) 4 cm
(C) 2 cm
(D) 3 cm

Dear Student,

Please find below the solution to the asked query:

We have two chords AB and CD intersect at P  ,

AP  =  2 cm  ,  BP  = 6  cm ,  CP  =  3 cm

We know "  Theorem  :  When two chords intersect each other inside or outside of the circle , The rectangle formed by two segment of one chord is equal in Area of rectangle formed by two segment of other chord . "

So , we get

AP × BP  = CP ×  DP

So, substitute all values , we get

×  6  =   3  ×  DP

3 DP  =  12

DP =   4

So,

DP  =    3 cm , 

Therefore, 

Option ( B )                                                                                             ( Ans )


Hope this information will clear your doubts about Comparing Quantities .

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