Q.17 In the given figure, find the value of x in right angles       

Dear Student,
Here is the solution of your asked query:

Here we draw a line LMXYABLOQ=BQO = 150°     {alternate interior angles}And, LOP+XPO=180°     {Angles on same side of transversal}LOP+70°=180°LOP=180°-70°=110°So, x-10=LOP+LOQx-10=110°+150° x=270°
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