Q.5. Find the area enclosed by 2 x + 3 y ≤ 6 . Share with your friends Share 0 Abhishek Jha answered this Dear Student, Here is the solution of your asked query: Given, 2x+3y≤6So we take the lines,2x+3y=6and the area enclosed by these lines is the required areafor 1st quadrant,x>0,y>02x+3y=6which is plotted in the graph2nd quadrantx<0.y>0-2x+3y=6which is plotted in the graphx<0,y<0-2x-3y=6which is plotted in the graphx>0,y<02x-3y=6which is plotted in the graphhence from the figure we see that it forms a rhombusof side length=3-02+0-22=13units length of diagonals is 4and 6 units area=pq2=4×62=12 sq. units Regards 0 View Full Answer