Q.5. In the given figure, O B C   a n d   A B C are drawn on the same base, i-e., BC. If AB = AC and BO = OC, then prove that A B O = A C O .

Dear student,

since AB=ACACB=ABC         (1)        --[equal sides have equal angles opp. to them]also, given BO=OCOCB=OBC         (2)        --[equal sides have equal angles opp. to them]Subtracting (2) from (1) we get,ACB-OCB=ABC- OBCABO=ACOHence proved

  • 1
Question no. 5
  • 0
please send the whole question sucker
  • 0
What are you looking for?