# Q. A block of mass m = 1/3 kg is kept on a rough horizontal plane. Friction coefficient is $\mu $= 0.75. The work done by minimum force required to drag the block along the plane by a distance 5 m, is W joule, then find the value of W.

The minimum force required to pull the object upwards is ,

So here the work done will be ,

W = Fs cos$\theta $

$Herethegivenvaluesare,s=5m,\mu =0.75andm=\frac{1}{3}kg\phantom{\rule{0ex}{0ex}}butthevalueofinclinationthatis\theta isnotgiven.\phantom{\rule{0ex}{0ex}}Sokindlyputthevalueof\theta intheequationandgettheresult.$

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