Q., Current through branch AB Share with your friends Share 0 Vijay Shankar Yadav answered this Dear Student, Here 2 and 2 ohm resisters are in parallel and another 2ohm in series with them so net resistance of this combination =2×22+2+2=3ohm and current through this =33=1ABranch AB has one of 2ohm of parallel combiation hence current will equally divide in them So current in AB=.5A Regards -2 View Full Answer