Q Find the period of a vibrating particle which has acceleration of 48 cms-2, when displacement from mean position - Maths - Limits and Derivatives

Question

Q Find the period of a vibrating particle which has acceleration of
48 cm s - 2 , when displacement from mean position is 12 cm Assume
motion to be S H M

Shobhit Mittal · Accepted Answer

a=0
48 m/s2sice accn is positive the displacement from the mean position is -ve that is -0
12 m angular position of the particle=sin--0
12Aa=-Aω2sinωt    accn eqn ωt=sin--0
12A   angular position for a=0
48 m/s20 48=-Aω2sinsin--0 12A0 48=ω20
12ω=4812=4=2 rad /sT=2πω=2π2=π sec time period Regards

Q. Find the period of a vibrating particle which has acceleration of 48 cm s - 2 , when displacement from mean position is 12 cm. Assume motion to be S.H.M.

Q. Find the period of a vibrating particle which has acceleration of 48 cm $s^{- 2}$ , when displacement from mean position is 12 cm. Assume motion to be S.H.M.