Q). Five straight line segments interest at a common point and five triangles are constructed as shown in the figure. What is the total sum of the 10 angles marked on the diagram? Share with your friends Share 1 Brijendra Pal answered this Hi, We know that vertically opposite angles are equal so angle 1 = angle 1 and angle 2 = angle 2 , etcare 5 pairs of opposite vertical angle and they are equal now we know that sum of all these 10 angles will be 360 degree due to property that around a point sum of all the angles is 360 degreeso 2∠1+∠2+∠3+∠4+∠5 = 360∠1+∠2+∠3+∠4+∠5= 180 .....1Now there are 5 triangles and sum of all the angles in a triangleis always 180 degree. So sum of all the angles of 5 triangles=180×5 = 900so when we will add all the marked angles and angles 1,2,3,4,5then we have two set first is sum of all the angles that are marked and sum of angles 1,2,3,4,5so sum of all the marked angles+∠1+∠2+∠3+∠4+∠5=900sum of all the marked angles= 900-∠1+∠2+∠3+∠4+∠5=900-180= 720 degree 3 View Full Answer Nijerson answered this we can consider them as X for every triangle it will be 2x+y=180 2x=180-y when addding this 180-y+180-y+180-y+180-y+180-y which will be 900+5y -1 Somdipta Basu answered this 600 -1
