# $Q-{\mathrm{tan}}^{2}\theta -{\mathrm{sin}}^{2}\theta ={\mathrm{tan}}^{2}\theta {\mathrm{sin}}^{2}\theta \phantom{\rule{0ex}{0ex}}Q-\frac{\mathrm{tan}\theta}{1-cot\theta}+\frac{cot\theta}{1-\mathrm{tan}\theta}=sec\theta \mathrm{cos}ec\theta +1$

Since you have not mentioned question number so doing as per my understanding.

Kindly refer the link for your first query.

https://www.meritnation.com/ask-answer/question/prove-that-tan2a-sin2a-tan2a-sin2a/introduction-to-trigonometry/3035918

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