Q The letters of the word "PROBABILITY" are placed in a bag and one letter is taken out - Maths - Data Handling

Question

Q The letters of the word "PROBABILITY" are placed in a bag and one
letter is taken out
i There are outcomes

ii What is the probability of the following being the one taken
out?
a) P ( P) = (b) P (R) = (c) P(B) =
d) P (I) = (e) P (vowels ) = (f) P (consonants) =
g) P (X) = (h) P (any letter) =

Decoder_7 · Accepted Answer

(i) There are 11 outcomes as there are
total of 11 letters in the word "PROBABILITY"

[ii] (a) Probability= Favourable
outcomesâ€‹
Total Number of outcomes

P(P)= 1/11 (Since 'P' is one in number and total number of outcomes
are eleven)

(b) P(R)=1/11(Since'R' is one in number and total number of
outcomes are eleven)

(c) P(B)= 2/11(Since 'B' is two in number and total number of
outcomes are eleven)

(d) P(I)=2/11(Since'I' is two in number and total number of
outcomes are eleven)

(e) P(vowels)= 4/11(Since there are four vowels in number namely
two 'I's,one each of 'A' & 'O' and total number of outcomes are
eleven)

(f ) P(Consonants)= 7/11(Since there are total of 11 letters out of
which 4 are vowels and hence rest are consonants)
(g) P(X)= 0/11( Since 'X' is not there in the word PROBABILITY)

(h) P(any letter)= 11/11=1(Since out of 11 any letter can be
picked)