Q. The letters of the word "PROBABILITY" are placed in a bag and one letter is taken out.
i There are .................... outcomes.

ii What is the probability of the following being the one taken out? 
a) P ( P) = ....................         (b) P (R) = ............................                            (c) P(B) = ..................
d) P (I) = .....................          (e) P (vowels ) = ...................                            (f) P (consonants) = ...........
g) P (X) = ...................           (h) P (any letter) = .................


 

(i) There are     11     outcomes as there are total  of 11 letters in the word "PROBABILITY".


[ii]  (a) Probability=  Favourable outcomes​         
                                  Total Number of outcomes

           P(P)= 1/11  (Since 'P' is one in number and total number of outcomes are eleven)


        (b)   P(R)=1/11(Since'R' is one in number and total number of outcomes are eleven)

        (c)   P(B)= 2/11(Since 'B' is two in number and total number of outcomes are eleven)

        (d)  P(I)=2/11(Since'I' is two in number and total number of outcomes are eleven)

        (e)  P(vowels)= 4/11(Since there are four vowels in number namely two 'I's,one each of 'A' & 'O' and total number of outcomes are eleven)


        (f ) P(Consonants)= 7/11(Since there are total of 11 letters out of which 4 are vowels and hence rest are consonants)     
        (g) P(X)= 0/11( Since 'X' is not there in the word PROBABILITY)

         (h) P(any letter)= 11/11=1(Since out of  11 any letter can be picked)                    
 

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ii)
1. 1/11
2. 1/11
3. 2/11
4. 2/11
5. 4/11
6. 7/11
7. 0/11
8. 11/11
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